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TODGA/正十二烷萃取Am(Ⅲ)的动力学

朱文彬, 叶国安, 李峰峰, 李会蓉

朱文彬, 叶国安, 李峰峰, 李会蓉. TODGA/正十二烷萃取Am(Ⅲ)的动力学[J]. 核化学与放射化学, 2013, 35(3): 136-143. DOI: 10.7538/hhxyfshx.2013.35.03.0136
引用本文: 朱文彬, 叶国安, 李峰峰, 李会蓉. TODGA/正十二烷萃取Am(Ⅲ)的动力学[J]. 核化学与放射化学, 2013, 35(3): 136-143. DOI: 10.7538/hhxyfshx.2013.35.03.0136
ZHU Wen-bin, YE Guo-an, LI Feng-feng, LI Hui-rong. Extraction Kinetics Behavior of Am(Ⅲ) by TODGA[J]. Journal of Nuclear and Radiochemistry, 2013, 35(3): 136-143. DOI: 10.7538/hhxyfshx.2013.35.03.0136
Citation: ZHU Wen-bin, YE Guo-an, LI Feng-feng, LI Hui-rong. Extraction Kinetics Behavior of Am(Ⅲ) by TODGA[J]. Journal of Nuclear and Radiochemistry, 2013, 35(3): 136-143. DOI: 10.7538/hhxyfshx.2013.35.03.0136

TODGA/正十二烷萃取Am(Ⅲ)的动力学

Extraction Kinetics Behavior of Am(Ⅲ) by TODGA

  • 摘要:N,N,N′,N′-四辛基-3-氧戊二酰胺(TODGA)为萃取剂,正十二烷为稀释剂,研究了该萃取体系在恒界面池中萃取Am(Ⅲ)的动力学,考察了搅拌转速、两相界面面积、萃取剂浓度、金属离子浓度、酸度和温度等因素对Am(Ⅲ)萃取行为的影响,并推导了相应的萃取机理。结果表明:(1) 搅拌转速在130 r/min以下时,0.1 mol/L TODGA/正十二烷萃取Am(Ⅲ)的过程为扩散控制类型,在搅拌转速为150 r/min以上时,则属于化学反应控制的动力学控制模式;(2) 求得了在(170±2) r/min、温度为(25±0.1) ℃时0.1 mol/L TODGA/正十二烷萃取Am(Ⅲ)的初始速率方程:
    r0=(dcorg(M)/dt)t=0=k•(S/V)c0.94aq,0(Am)c1.05aq,0(HNO3)c1.19org,0(TODGA)
    在25℃下,求得表观速率常数k=(24.2±3.4)×10-3mol-2.18•L2.18•min-1•cm;(3) 0.1mol/L TODGA/正十二烷萃取Am(Ⅲ)的初始速率随着温度的升高而增大,求得表观活化能Ea=(25.94±0.98)kJ/mol。
    Abstract: In the present paper, N, N, N′, N′-tetraoctyl diglycolamide(TODGA) as the extractant and n-dodecane as the diluent, the extraction kinetics behavior of Am(Ⅲ) in TODGA/n-dodecane HNO3 system was studied, including stirring speed, the interfacial area, extractant concentration in n-dodecane, extracted ions concentration, acidity of aqueous phase and temperature. The results show that the extraction process is controlled by diffusion under 130 r/min of stirring speed and by chemical reaction above 150 r/min. The extraction rate equation and the apparent extraction rate constant of Am(Ⅲ) by TODGA/ n-dodecane  in (170±2) r/min and (25±0.1)℃ are as follows:
     r0=(dcorg(M)/dt)t=0=k•(S/V)c0.94aq,0(Am)c1.05aq,0(HNO3)c1.19org,0(TODGA)
     k=(24.2±3.4)×10-3mol-2.18•L2.18•min-1•cm,Ea=(25.94±0.98)kJ/mol.
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  • 刊出日期:  2013-06-19

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